If x = -1 the value of x2+2x+1

[tex]p({x}) = x {}^{2} + 2x + 1 \\ p({ - 1}) = ( - 1) {}^{2} + 2 \times ( - 1) + 1 \\ = 1 - 2 + 1 \\ = 2 - 2 \\ = 0 \: ans[/tex]

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Substitute

=(-1)2+2(-1)+1

= -2-2+1

= -4+1

= -3