3x+y=1 (2k-1)x+(k-1)y=2k+1

3x + y = 1

y = 1- 3x

putting value of y in (2k-1)x + (k-1)y = 2k +1

2kx - x + (k-1)(1-3x) = 2k

2kx - x + k -3kx - 1 + 3x = 2k

2x - Kx - k +1 = 0

x(2-k) = k-1

x =(k-1)/(2-k)

and y = 1- 3(k-1)/(2-k)