evaluate : log2401 to the base cube root 7​

plz make it clear and easy

Answer:

Step-by-step explanation:

log2401 to the base 3√7. = log(7)^4 to the base 3√7. = log(3√7)^12 to the base 3√7 = y ( let ) We know that: N=a^x & x= logN to the base a. Here , N=2401= (7)^4=(3√7)^12 and a =3√7. Now ,. (3√7)^12 =( 3√7 )^y y=12 = log 2401 to the base 3√7