HELP ME PLEASE!!!!!! The body of a 154-pound person contains approximately 2 X 10^-1 milligrams of gold and 6 X 10^1 milligrams of aluminum. Based on this infor

The number of milligrams of aluminium in the body is 300 times the number of milligrams of gold in the body.

Given amount of gold is = g =  [tex]2 * 10^{-1}[/tex] mg.

Given amount of aluminium is = a = [tex]6*10^1[/tex] mg.

Let the number of milligrams of aluminium in the body is "k" times the number of milligrams of gold in the body.

So, a = kg

[tex]k=\frac{a}{g}\\k=\frac{6\cdot10^{1}}{2\cdot10^{-1}}\\k=300[/tex]

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