HELP ME PLEASE!!!!!! The body of a 154pound person contains approximately 2 X 10^1 milligrams of gold and 6 X 10^1 milligrams of aluminum. Based on this infor
Mathematics
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HELP ME PLEASE!!!!!!
The body of a 154pound person contains approximately 2 X 10^1 milligrams of gold and 6 X 10^1 milligrams of aluminum. Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?
The body of a 154pound person contains approximately 2 X 10^1 milligrams of gold and 6 X 10^1 milligrams of aluminum. Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?
1 Answer

1. User Answers Cetacea
The number of milligrams of aluminium in the body is 300 times the number of milligrams of gold in the body.
Given amount of gold is = g = [tex]2 * 10^{1}[/tex] mg.
Given amount of aluminium is = a = [tex]6*10^1[/tex] mg.
Let the number of milligrams of aluminium in the body is "k" times the number of milligrams of gold in the body.
So, a = kg
[tex]k=\frac{a}{g}\\k=\frac{6\cdot10^{1}}{2\cdot10^{1}}\\k=300[/tex]
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